public abstract class AbstractSearchResultPage extends Object implements SearchResultPage
SearchResultPage interface.| Modifier and Type | Class and Description |
|---|---|
private class |
AbstractSearchResultPage.HitIterator
This inner class is used to iterate the hits.
|
| Modifier and Type | Field and Description |
|---|---|
private int |
hitsPerPage |
private int |
pageCount |
private int |
pageIndex |
private String |
query |
private int |
totalHitCount |
DEFAULT_HITS_PER_PAGE| Constructor and Description |
|---|
AbstractSearchResultPage(String searchQuery,
int totalHits,
int hitPerPage,
int pageNumber)
The constructor.
|
| Modifier and Type | Method and Description |
|---|---|
int |
getHitEndNumber()
This method gets the absolute number of the last hit of this page.
|
int |
getHitsPerPage()
|
int |
getHitStartNumber()
This method gets the absolute number of the first hit of this page.
|
int |
getPageCount()
This method gets the number of pages used to split the
total hits. |
int |
getPageIndex()
This method gets the index of the page represented by this
search result, where
0 is the first page and is the last page. |
int |
getPagingEndIndex(int pagingRange)
This method gets the
page-index of the end page when a
number (pagingRange*2)+1 links should be rendered for paging. |
int |
getPagingStartIndex(int pagingRange)
This method gets the
page-index of the start page when a
number (pagingRange*2)+1 links should be rendered for paging. |
String |
getQuery()
This method gets the original query string that produced this result.
|
int |
getTotalHitCount()
This method gets the total number of hits for this
query. |
Iterator<SearchHit> |
iterator() |
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, waitgetPageHit, getPageHitCountforEach, spliteratorprivate final String query
getQuery()private final int totalHitCount
getTotalHitCount()private final int hitsPerPage
getHitsPerPage()private final int pageCount
getPageCount()private final int pageIndex
getPageIndex()public AbstractSearchResultPage(String searchQuery, int totalHits, int hitPerPage, int pageNumber)
searchQuery - is the query that caused this page.totalHits - is the total number of hits.hitPerPage - is the number of hits per page.pageNumber - is the index of this page.public int getHitsPerPage()
getHitsPerPage in interface SearchResultPageSearchResultPage.DEFAULT_HITS_PER_PAGEpublic int getPageCount()
total hits. An empty
search result will have one empty page.getPageCount in interface SearchResultPagepublic int getPageIndex()
search result, where
0 is the first page and SearchResultPage.getPageCount() - 1 is the last page.getPageIndex in interface SearchResultPagepublic String getQuery()
getQuery in interface SearchResultPagepublic int getTotalHitCount()
query.getTotalHitCount in interface SearchResultPagepublic int getHitStartNumber()
SearchResultPage.getPageIndex()*SearchResultPage.getHitsPerPage()+ 1
getHitStartNumber in interface SearchResultPagehit of this page.public int getHitEndNumber()
SearchResultPage.getHitStartNumber()+SearchResultPage.getPageHitCount()
getHitEndNumber in interface SearchResultPagehit of this page.public int getPagingStartIndex(int pagingRange)
page-index of the start page when a
number (pagingRange*2)+1 links should be rendered for paging. The pagingRange
actually specifies the number of links forward and backwards. result-pages is potentially NOT limited. To avoid that your GUI
layout gets broken by too many paging links, you can use this method to render a fixed number of paging
links. pagingCount is 2 and you would have a page-count of e.g.
10. Then you would render links for visiting the pages from 0 to 4
if your page-index is 0,1 , or 2. For a
page-index of 3, you would render the links from 1 to
5 and so on. getPagingStartIndex in interface SearchResultPagepagingRange - the number of paging links forward and backwards.page-index to start paging with.SearchResultPage.getPagingEndIndex(int)public int getPagingEndIndex(int pagingRange)
page-index of the end page when a
number (pagingRange*2)+1 links should be rendered for paging. The pagingRange
actually specifies the number of links forward and backwards. result-pages is potentially NOT limited. To avoid that your GUI
layout gets broken by too many paging links, you can use this method to render a fixed number of paging
links. pagingCount is 2 and you would have a page-count of e.g.
10. Then you would render links for visiting the pages from 5 to 9
if your page-index is 7,8 , or 9. For a
page-index of 6, you would render the links from 4 to
8 and so on. getPagingEndIndex in interface SearchResultPagepagingRange - the number of paging links forward and backwards.page-index to end paging with.SearchResultPage.getPagingStartIndex(int)Copyright © 2001–2016 mmm-Team. All rights reserved.